Redshifting as ‘tired light’ does not lose energy over distance

There seems to be a flaw in the assumption that cosmological redshift of galaxies first observed by Hubble and others in the 1920s cannot be explained by tired light because there is no explanation as to how light ‘loses’ energy over distance. The argument being a “photon” of light at 100nm has more energy than one at 200nm. But this seems to overlook a fundamental point which is that a light beam with a wavelength range of 100-200nm when redshifted to 200-400nm still has the same total energy as the rest frame emitted range. But just spread out across a range double that of the original rest frame emission range.

My question is: A source emits a constant amount of energy as EMR with a range of 100-200 nm. Will the measured total energy of that emission by an observor be the same for the rest frame beam of 100-200nm as it would be for the same beam redshifted to 200-400nm beam during the same observation time frame?

My assumption is that where 100-200 nm gets redshifted to a longer wavelength the energy is *still conserved*. Just spread out across a larger wavelength range. Contrary to and negating the argument used by Big Bang theorists that a tired light non expanding universe would have to explain how light “loses” energy.

Redshift Distance relationship in a non expanding model of the universe

 Redshift/Distance relationship for a Non expanding model

In cosmology redshift is given by the letter z.  The z to wavelength relationship in an expanding model works as follows:

A restframe source emits a wavelength range of 500-1000 nm. At z= 1 it doubles to an observed range of 1000-2000. At z=2 the range is 1500 to 3000. At z=3 the range is redshifted to 2000 to 4000 etc. The distance to the source in an expanding model is explained and given as velocity in km/s. The higher the redshift the faster it is moving away from us and the farther away it is. 

In other words the distance to a source at z=2 in an expanding model is much farther than predicted for a non expanding model because in a non expanding universe the source is not moving away from the observer on earth. So that for instance in a non expanding model a star at z=2 is twice as far away from earth as a star at z=1 is from earth.

Unfortunately to date the best confirmed real actual distance of any star from earth is much less than z=1. Which is z=0.1 to the Virgo cluster. The table below assumes distance X at z=1 is a known actual real distance and not an assumed distance related to velocity, as is the case in a Big Bang universe. 

z=0 (500nm to 1000nm ) = restframe

z= 1 (1000 to 2000)=distance A

z=3  (2000 to 4000)=distance 2xA

z=7 (4000 to 8000)=distance 3xA

z=15 (8000 to 16000)

z=31 (16000 to 32000)

z=63 (32000 to 64000)

z=127

z=255

z=511

z=1023(ie Microwave)=distance 10xA

Therefore in a non expanding universe z=1023 is only twice as far away as z=31. Or 10 times as far away as an object at z=1 

So far the current available limits of detection in optical are via the JWST mid infrared camera. ( JWST MIR camera range is 5-28 microns. Equivelent to a redshift range of z=9 to z=49)

The big question is...how far away is z=1 in a non expanding model?

That will be hard to quantify as so far only the Virgo cluster at approx z=0.001 has a known real distance. Using various methods like parralax. 

Thus in a non expanding universe the CMBR is explained as redshifted light from galaxies at and around z=1023. That is galaxies at around 10 times the distance from earth as any source observed at a distance where the light is redshifted to z=1.

The average black body spectrum of all the billions of stars in that distance parameter around z=1023 combine to give the observed CMBR. And because at that distance there is still a small variation in distribution of galaxies this also accounts for the slight graininess observed in the COBE CMBR images.

Black Holes in M87 and Sag A

 Recent news from Event Horizon Telescope consortium is a new discovery of a black hole at sag A in our Milky Way. With an image surprisingly similar to the BH in M87

Notice M87 didn’t have a mandatory accretion disc. The rather disingenuous excuse from NASA is that by some remarkeable coincidence the BH is face on to us. The only angle that an accretion disc wouldn’t show up in observations. I said back then this is a failed image of an imaginary BH with a lousy excuse to legitimise the image not having a mandatory accretion disc. 

Guess what? The BH in sag A also doesn’t have an accretion disc either. And guess what NASA’s excuse is this time? 

“If confirmed this means that from our vantage point we are looking down on Sgr A* and its ring more than we are from side-on, surprisingly similar to EHT's first target M87*.”(NASA)

Another amazing coincidence to back up a failed prediction about Black Holes by theorists? Or just an imaginary BH from a unsubstantiatable theory.