Supernova (Sn1a)
lightcurves have been used to illustrate time dilation due to the Big Bang
expansion. This is an argument that has failed to follow a rigorous scientific
method. The authors of these papers should have also tried to see if the
observed lightcurve data fits a non expanding, z=0 model. Using data from Knop et al 2003 I have
created graphs of lightcurves where there is no expansion (z=0). The following graphs are Knops dilated
lightcurve graphs on the left and for comparison, graphs of undilated fits on the right. These
show how the data can also fit a non expanding model.
Physics described using wave only electromagnetic radiation and classical mechanics.
Thursday, 22 October 2015
Saturday, 23 August 2014
Gamma ray bursts and Fast radio bursts: A Theoretical model
Gammaraybursts and Fast Radio Bursts: A Classical Model.
This page was originally published 2000-2014 at gammarayburst.com
The following description of a GRB model can also be used to explain
more recent FRB observations. Essentially a FRB is a very fast GRB where
wavelengths shorter than radio are too short in duration to be observed.
In a non expanding universe of infinite age and size, observors should see
emr from all directions and from great cosmological distances. This assumes
a non Big Bang universe not conforming to the laws of relativity. At these
scales some stellar sources will actually be moving away from the earth at
speeds greater than c. The earth then must be travelling away from the
source, at speeds greater than c and we would therefore overtake this light
and "see" the light in reverse. That is, what appears to be a flash above us is
actually light we are overtaking from the opposite direction below our feet.
Much as a fast boat can overtake slower waves on water and the waves
appear to be coming towards the observer in the prow of the boat when
in fact they are travelling in the same direction as the boat but at a slower
speed. Taking into account the assumption that we would always be
decellerating in relation to the source of the light, the burst would first
be seen as more blue shifted (at the gamma end of the spectrum) and as
time progresses observations in longer wavelengths would be observed.
So the original gamma lightcurve profile would be seen stretched out
over longer time frames in longer wavelengths . If the burst was for
20 seconds in gamma and 200 in optical and then it would be seen for
2000 sec in radio. But always show the same distinctive profile for each
burst in various parts of the observed spectrum.
For a brief visual explanation of this see..
http://www.youtube.com/watch?v=QLSfmvFcLB8
The model I describe here predicts that the afterglows in different parts
of the emr spectrum will be similar in profile to that of the gammaray
lightcurve, but with different timescales. This is consistent with all
observations and shown in the illustration below. The graph below shows
this in data from grb 970508. Using gamma, optical and radio observations.
The prediction would be that other unmeasured lightcurves like x-rays
would also have similar profiles as their counterpart in gamma.
The shorter the wavelength the shorter the timescale. That is; in x ray
the burst duration would be shorter than optical and longer than gamma.
In the comparison graph below, between the 3 lightcurves, a self
similarity of lightcurve profiles from different parts of the emr spectrum
is observed. The length of the afterglow is directly proportional to the
wavelength. It also indicates that if gamma and optical burst time lengths
very were small, on the order of smaller than milliseconds. Then in radio,
these bursts would be observed having time scales in millisconds. And
that there would be measurable delays between shorter and longer
radio wavelengths. This is confirmed by recent Fast Radio Burst
observations.
This page was originally published 2000-2014 at gammarayburst.com
The following description of a GRB model can also be used to explain
more recent FRB observations. Essentially a FRB is a very fast GRB where
wavelengths shorter than radio are too short in duration to be observed.
In a non expanding universe of infinite age and size, observors should see
emr from all directions and from great cosmological distances. This assumes
a non Big Bang universe not conforming to the laws of relativity. At these
scales some stellar sources will actually be moving away from the earth at
speeds greater than c. The earth then must be travelling away from the
source, at speeds greater than c and we would therefore overtake this light
and "see" the light in reverse. That is, what appears to be a flash above us is
actually light we are overtaking from the opposite direction below our feet.
Much as a fast boat can overtake slower waves on water and the waves
appear to be coming towards the observer in the prow of the boat when
in fact they are travelling in the same direction as the boat but at a slower
speed. Taking into account the assumption that we would always be
decellerating in relation to the source of the light, the burst would first
be seen as more blue shifted (at the gamma end of the spectrum) and as
time progresses observations in longer wavelengths would be observed.
So the original gamma lightcurve profile would be seen stretched out
over longer time frames in longer wavelengths . If the burst was for
20 seconds in gamma and 200 in optical and then it would be seen for
2000 sec in radio. But always show the same distinctive profile for each
burst in various parts of the observed spectrum.
For a brief visual explanation of this see..
http://www.youtube.com/watch?v=QLSfmvFcLB8
The model I describe here predicts that the afterglows in different parts
of the emr spectrum will be similar in profile to that of the gammaray
lightcurve, but with different timescales. This is consistent with all
observations and shown in the illustration below. The graph below shows
this in data from grb 970508. Using gamma, optical and radio observations.
The prediction would be that other unmeasured lightcurves like x-rays
would also have similar profiles as their counterpart in gamma.
The shorter the wavelength the shorter the timescale. That is; in x ray
the burst duration would be shorter than optical and longer than gamma.
In the comparison graph below, between the 3 lightcurves, a self
similarity of lightcurve profiles from different parts of the emr spectrum
is observed. The length of the afterglow is directly proportional to the
wavelength. It also indicates that if gamma and optical burst time lengths
very were small, on the order of smaller than milliseconds. Then in radio,
these bursts would be observed having time scales in millisconds. And
that there would be measurable delays between shorter and longer
radio wavelengths. This is confirmed by recent Fast Radio Burst
observations.
Saturday, 5 July 2014
Fractal Atomic numbers
The illustration/graph compilations on this page highlite the
similarities between features in the graphs of atomic number
vs. element conductivity. Repeating patterns and self
similarity between small and large sections of the original
red graph suggest a fractal element to the arrangement
of atomic numbers and their associated properties.
Initially consider the the four highest conducting elements
(Be, Al, Cu, Ag and Au) They increase their atomic numbers
at very near the same rate as the increase seen in the noble
gases The increases are shown in the example below .
For instance, between Ag and Au the increase in conductivity
is 32. Note the same increase in atomic number, 32, is
seen in the noble gases between Xe and Ra...
Be(4) Al (13) Cu(29) Ag (47) Au ( 79) - best conductors
9 16 18 32
Ne(10) Ar(18) Kr( 36) Xe (54) Ra (86) - noble gases
8 18 18 32
In the illustrations supplied the original graph of element
conductivity vs atomic number is in red. Overlayed in the
illustrations are graphs of various repeating patterns. These
graph sections are taken from the original red graph and
either placed size as in different parts of the illustration
or enlarged or reduced and repositioned onto the red graph
to show similarities in profile.
In the first illustration these samples are labelled as sets
1 to 5 in the table below. For instance, sets 3,4 and 5 show
how the main peaks in the red conductivity graph between
Calcium (20) and Copper (29), are in fact a repeating
pattern found in other parts of the red graph.
Also, set 1 shows how the section from the main red graph
In the first illustration these samples are labelled as sets
1 to 5 in the table below. For instance, sets 3,4 and 5 show
how the main peaks in the red conductivity graph between
Calcium (20) and Copper (29), are in fact a repeating
pattern found in other parts of the red graph.
Also, set 1 shows how the section from the main red graph
between Be (4) and Ag (47) , once enlarged , very closely
matches that of the section in the main red graph between
Be (4) and Au (79).
In the second illustration a section from the red graph up to
atomic number of Ag is stretched to 2 different sizes and
re-overlayed onto the red graph to show how a fractal element
can be seen in small and large sections of the red graph
In the second illustration a section from the red graph up to
atomic number of Ag is stretched to 2 different sizes and
re-overlayed onto the red graph to show how a fractal element
can be seen in small and large sections of the red graph
Set 1
Be Ca Cu Ag Au
4 20 29 47 79
matches
Be Al Ca Cu Ag
4 13 20 29 47
Set 2
Cu Rb Mo Ag
29 37 42 48
matches
Ca Cr Co Cu
20 24 27 29
REPEATING PATTERNS...
Set 3
Ca Cr Co Cu
20 24 2 7 29
matches
Be - Na Al
4 - 11 13
Set 4
Ca Cr Co Cu
20 24 27 29
matches
Rb Mo Rh Ag
37 42 45 48
Set 5
Ca Cr Co Cu
20 24 27 29
matches
Yb W Ir Au
70 74 77 79
Thursday, 8 May 2014
How the ancients cut their stone slabs
There are stones found in prehistoric sites that are unusually smooth and flat.
With joins that have very tight fits. And very flat outer surfaces. There are two
possible low-tech methods that I thought could explain the flatness and
smoothness of the stones The first is a method I saw as kid on an NFB short
about Inuit igloo making skills. As the blocks of hardened snow have to be snug
fit and at odd angles due to the dome shape, the Inuit rough cut the hardened
snow blocks with little metal hand saws ( the snow is easy to cut).
They then rough fit them in place and then using the saw they saw up and down
in the joining space between the blocks. Slowly removing any uneven surfaces
on either block. The result is a tight fit at the right angle.
Although rock is a different harder material I thought a similar technique could
be used. Rough cut the blocks. Put in place, and then between the two blocks that
need fitting, insert a large metal saw and start cutting up and down in the crack.
Every so often opening up the space between the two blocks and blowing out the
sandy residue.
Theoretically this would, like the igloo snow blocks, remove any unevenness
between the blocks and presumably give a join that's straight and snug.
The second is how to get a flat outer face on the large slabs. One idea I had
was based on the milling stones that grind flour...Place the rough cut
5 X 10 foot slab that needs to be smoothed onto the ground. With the face up
that needs to be flattened and smoothed. Then place on top, a large circular
milling stone preferably already sufficiently flat. Make it 10 foot diameter
with a handle(s) on its perimeter inserted to allow slaves to rotate and grind
the slab underneath. Although Ive never tried this myself I think it might give
a flat surface if enough circular grinding is applied to the lower slab. It may
be important to *not* allow the circular grinding stone to always rotate on the
same spot as this may not give such a flat finish.
With joins that have very tight fits. And very flat outer surfaces. There are two
possible low-tech methods that I thought could explain the flatness and
smoothness of the stones The first is a method I saw as kid on an NFB short
about Inuit igloo making skills. As the blocks of hardened snow have to be snug
fit and at odd angles due to the dome shape, the Inuit rough cut the hardened
snow blocks with little metal hand saws ( the snow is easy to cut).
They then rough fit them in place and then using the saw they saw up and down
in the joining space between the blocks. Slowly removing any uneven surfaces
on either block. The result is a tight fit at the right angle.
Although rock is a different harder material I thought a similar technique could
be used. Rough cut the blocks. Put in place, and then between the two blocks that
need fitting, insert a large metal saw and start cutting up and down in the crack.
Every so often opening up the space between the two blocks and blowing out the
sandy residue.
Theoretically this would, like the igloo snow blocks, remove any unevenness
between the blocks and presumably give a join that's straight and snug.
The second is how to get a flat outer face on the large slabs. One idea I had
was based on the milling stones that grind flour...Place the rough cut
5 X 10 foot slab that needs to be smoothed onto the ground. With the face up
that needs to be flattened and smoothed. Then place on top, a large circular
milling stone preferably already sufficiently flat. Make it 10 foot diameter
with a handle(s) on its perimeter inserted to allow slaves to rotate and grind
the slab underneath. Although Ive never tried this myself I think it might give
a flat surface if enough circular grinding is applied to the lower slab. It may
be important to *not* allow the circular grinding stone to always rotate on the
same spot as this may not give such a flat finish.
Monday, 28 October 2013
A neodium magnet falling through a copper pipe has its rate of descent, through the pipe, slowed. An effect similar to a magnet being pushed through a copper solenoid. Inserted here is a 3 drawing illustration showing top and 3/4 views of an experimental setup that tries to duplicate the copper pipes` "electro"-magnetic interaction on the falling magnet. In these illustrations Ive tried to replicate the effect of copper being moved past the magnet by having 5 rotating copper rimmed wheels with their rims pointing inwards in a star pattern as best seen in the top view section of the illustration.
The intent of this design is to try to rotate all 5 of the copper rimmed wheels at the same steady speed. Fast enough to levitate the magnet. Presumably varying the speed of rotation will change the height of the magnet . Not included in these illustrations is a means by which to constrain the magnet from flipping or moving away from the central axis , marked x in the illustrations. To do this maybe a vertical transparent plastic tube around the magnet could be added. To keep the magnet positioned above the axis but free to move up and down.
The intent of this design is to try to rotate all 5 of the copper rimmed wheels at the same steady speed. Fast enough to levitate the magnet. Presumably varying the speed of rotation will change the height of the magnet . Not included in these illustrations is a means by which to constrain the magnet from flipping or moving away from the central axis , marked x in the illustrations. To do this maybe a vertical transparent plastic tube around the magnet could be added. To keep the magnet positioned above the axis but free to move up and down.
Thursday, 5 September 2013
Light from double star system is consistent with emission theory
Supplied illustration refers to the wikipedia /de sitter illustration from the wiki page on emmision theory refutation, showing light coming off of the rotating star at c+v (in the illustration frame)
This illustration shows how the light , although travelling at a constant c+v in the illustration frame,
is also travelling at variable speeds relative to the rotatng star source. This contradicts what is observed in MMx. In MMx light is shown to always travel at the same speed in all directions in the source frame.
The straight line across the illustration is the path of the "photon". The circular line is the path of the rotating stellar source. The numbers refer to where the light will be for each time frame where the time frame is an equal series of lengths of time .
So in frame 1 the light is just leaving the star. In frame 2 the light has travelled distance x from the source at (c+v) and the source has rotated 1/4 turn . In frame 3 the light has travelled the same distance x again and the light source has rotated another turn. Etc etc.
If one then takes the edge of a piece of paper and measures the orange lines linking 2-2, 3-3, 4-4, and 5-5 and then compares the lengths of each of them . One will find that the lengths are all different.
(1-2 is shorter than 2-3. 3-4 is shorter than 2-3 but longer than 1-2 and 4-5)
This shows that the distance travelled by the light from the source is travelling at a variable speed, relative to the source. Even though it is observed to be travelling at a constant speed c+v in the reference frame of the illustration .
In other words the illustration in wiki that this refers to is incorrect. Light does not travel at variable
speeds relative to the source. MMx shows us this and in fact there is no known experimental observation that shows that light travels at variable speeds relative to the source.
A correct illustration would be of the light source not moving and the earth/observor moving in a circular motion on the page. This would then show us that light does not pile up as it leaves the source. It would only have a doppler shift added to it at the point of observation.
This illustration shows how the light , although travelling at a constant c+v in the illustration frame,
is also travelling at variable speeds relative to the rotatng star source. This contradicts what is observed in MMx. In MMx light is shown to always travel at the same speed in all directions in the source frame.
The straight line across the illustration is the path of the "photon". The circular line is the path of the rotating stellar source. The numbers refer to where the light will be for each time frame where the time frame is an equal series of lengths of time .
So in frame 1 the light is just leaving the star. In frame 2 the light has travelled distance x from the source at (c+v) and the source has rotated 1/4 turn . In frame 3 the light has travelled the same distance x again and the light source has rotated another turn. Etc etc.
If one then takes the edge of a piece of paper and measures the orange lines linking 2-2, 3-3, 4-4, and 5-5 and then compares the lengths of each of them . One will find that the lengths are all different.
(1-2 is shorter than 2-3. 3-4 is shorter than 2-3 but longer than 1-2 and 4-5)
This shows that the distance travelled by the light from the source is travelling at a variable speed, relative to the source. Even though it is observed to be travelling at a constant speed c+v in the reference frame of the illustration .
In other words the illustration in wiki that this refers to is incorrect. Light does not travel at variable
speeds relative to the source. MMx shows us this and in fact there is no known experimental observation that shows that light travels at variable speeds relative to the source.
A correct illustration would be of the light source not moving and the earth/observor moving in a circular motion on the page. This would then show us that light does not pile up as it leaves the source. It would only have a doppler shift added to it at the point of observation.
Saturday, 27 July 2013
Fizeau experiment results contradict Special Relativity
In the Fizeau experiment light travels at c/n (in the refractive index of water) when the water doesnt move through the experimental setup . But when the water flows at v through the setup towards the light source, as Fizeau did, the light travels at a slower speed through the pipe. But not by as much as if one subtracted the v of the water from c/n in water. This means that if you were to move with the water during the experiment (or better, you and the tube of water dont move and the light source does) then that means that the light is no longer moving through the water at c in the refractive index of water . And instead it is moving slightly faster or slower through the water then c in water would normally give. Depending on the direction of the flow of the water relative to the source. The irony of this is that, although Einstein apparently said this effect was an important consideration in devising SR. It also is true, that the Fizeau effect is proof that the speed of light in water can be c+-v, if the source moves relative to the observor. Contradicting the prediction of SR that light is always travelling at c for that medium.
The speed of light defined by the usual (Fizeau formula) is..
c/n +-v(1-1/n^2),..where (1-1/n^2) =0.4347
This accurately predicts the observations.
In effect what is happening is that in the same amount of time t, as when the water doesn’t flow, more water has to be travelled through by the lightbeam as it travels from source to detector. This means that the water becomes more dense as a refractive medium. So a classical calculation should reflect this by multiplying the refractive index by the refractive index to find out how the added v of the water affects the light speed.
Aside from Fizeau’s original formula, cited above, there are various other fairly straightforward ways to calculate the observed speed differences in Fizeau that I have formulated. Including:
The speed of light defined by the usual (Fizeau formula) is..
c/n +-v(1-1/n^2),..where (1-1/n^2) =0.4347
This accurately predicts the observations.
In effect what is happening is that in the same amount of time t, as when the water doesn’t flow, more water has to be travelled through by the lightbeam as it travels from source to detector. This means that the water becomes more dense as a refractive medium. So a classical calculation should reflect this by multiplying the refractive index by the refractive index to find out how the added v of the water affects the light speed.
Aside from Fizeau’s original formula, cited above, there are various other fairly straightforward ways to calculate the observed speed differences in Fizeau that I have formulated. Including:
c/n+-v{n^2-n}
where {n^2-n} = 0.4389
where {n^2-n} = 0.4389
Or: c/n+-v[{(n-1)+(n-1)}^2]
Or: c/n+-(V x (1-(n-1)/n)
(c/n+-(V x .67))/n
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